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Feb 21, 2023 at 15:27 vote accept Helmut
Feb 21, 2023 at 15:25 comment added Dan Boschen @Helmut all set, see my update
Feb 21, 2023 at 15:21 history edited Dan Boschen CC BY-SA 4.0
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Feb 21, 2023 at 15:17 comment added Helmut Thank you so much for the effort!
Feb 21, 2023 at 15:01 comment added Dan Boschen Let me update my answer later - the power is always a positive quantity and the distribution will be Chi squared (Rayleigh) so based on that there is a better way to do what you want along with an offset error for the case of white noise that I believe I detailed in another post … let me find that
Feb 21, 2023 at 14:42 comment added Helmut Oh man, that was actually obvious. Thanks! Is there a general way how to cope with the case $\sigma > \mu \rightarrow \mu - \sigma < 0$? Since the logarithm would not be defined in this case?
Feb 21, 2023 at 13:56 history answered Dan Boschen CC BY-SA 4.0