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lennon310
lennon310
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This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms, or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared, so AA or BB

This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared, so AA or BB

This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms, or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared, so AA or BB

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Seb Rose
Seb Rose
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This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared., so AA or BB

This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared.

This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared, so AA or BB

Source Link
Seb Rose
Seb Rose
  • 11
  • 1

This is only 8 years late, but the calculations above are different.

  1. Crosspower of AB / Autopower (AA)

  2. FFT(B)/FFT(A) is effectively (BB)/(AA) or autopower (B)/autopower(A)

I believe if you look at how Fast Fourier Transforms or in this case more likely Discrete Fourier Transforms (on a computer) are calculated, you will see that the amplitude is effectively squared.