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Dec 25, 2022 at 10:17 comment added Jdip @dorottopunto93 Check again, on my end I get the same exact result for Sx and periodogram(x). I am using your code.
Dec 25, 2022 at 10:09 comment added dorottopunto93 When I use Sx = 1/(2*pi*N)*abs(Sx).^2; the difference between periodogram and manual-calculated periodogram is 10 dB. I just wrote Sx as above, nothing changed in my code.
Dec 25, 2022 at 9:05 vote accept dorottopunto93
Dec 25, 2022 at 0:51 history answered Jdip CC BY-SA 4.0