Timeline for Understand carrier power, output power and dBC?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 25, 2022 at 22:20 | comment | added | Marcus Müller | As I already explained in my answer what you describe is not power relative to a carrier, but simply SNR. | |
| Aug 25, 2022 at 22:19 | comment | added | Marcus Müller | Just because you're centered around some center requency doesn't mean you transmit a carrier. But stating something in dBc requires that there is a carrier. There is really nothing to clarify here: without a carrier you can't state something as relative to the power of the carrier. | |
| Aug 25, 2022 at 20:01 | comment | added | Md. Hasan Rahman | However, I think you might be wrong in number 1 because power in frequency domain sum(X(k).^2)/Ndfft^2, where X(k) is the fft sample. If possible please clarify my doubt. (2) Sorry for not articulating my question in a proper way, but "You can only generate a noise with a given power in dB of carrier power if there's a carrier." what do you mean by if there is a carrier. Suppose for some signal set "B" Fc-is the center frequency which might interfere with an existing signal. The power defference between P_Sig-P_B=X; And X is in dBc. Am I missing somethin. | |
| Aug 25, 2022 at 19:49 | comment | added | Md. Hasan Rahman | Muller thank you for an explanation. | |
| Aug 25, 2022 at 13:21 | history | answered | Marcus Müller | CC BY-SA 4.0 |