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Dec 1, 2021 at 2:10 vote accept Wang Yun
Nov 30, 2021 at 8:14 comment added OverLordGoldDragon @WangYun If this answers your question, consider accepting.
Jul 16, 2021 at 9:10 history edited OverLordGoldDragon CC BY-SA 4.0
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Jul 16, 2021 at 9:04 comment added OverLordGoldDragon @WangYun Yes, but I admit the notation is lacking, it should really be with $\psi^{*}(t - b)$, alternatively $<f, \psi_b>$ - it's just brevity in original derivation. And the conjugate for the complex kernel is assumed by default. Edited.
Jul 16, 2021 at 9:04 history edited OverLordGoldDragon CC BY-SA 4.0
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Jul 16, 2021 at 8:53 comment added Wang Yun Is $<f,\psi>$ the integral $\int_{-\infty}^{+\infty} f(t)\psi(t) dt$?
Jul 16, 2021 at 8:49 comment added OverLordGoldDragon @WangYun Inner product; for discrete vectors, it's sum(a * b), for continuous functions, $\int_{-\infty}^{\infty} f(x) g(x) dx$. Here it's used for cross-correlation (of signal with wavelet, as a "similarity" measure), which is equivalently convolution with flipped kernel.
Jul 16, 2021 at 8:44 comment added Wang Yun What does <...,...>mean?
Jul 6, 2021 at 6:55 history answered OverLordGoldDragon CC BY-SA 4.0