Timeline for DFT modulus property?
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 7, 2023 at 11:31 | comment | added | OverLordGoldDragon | Unsure if you refer to your own use of the word or that you didn't see the comments but in case it's latter @robertbristow-johnson As far as I'm concerned "autopsy" is valid use. | |
| Jan 6, 2023 at 18:37 | comment | added | robert bristow-johnson | I'm pretty clueless @OverLordGoldDragon. Don't mind appreciation, but I'm clueless. | |
| Jan 6, 2023 at 16:13 | comment | added | OverLordGoldDragon | thanks @robertbristow-johnson (comments..) | |
| Jun 30, 2021 at 17:52 | comment | added | Marcus Müller | and the problem really seems to be that you don't really follow my or Dan's derivations – you're just opposing them. As said, I'll stop arguing here; it's sunk enough of my time. | |
| Jun 30, 2021 at 17:51 | comment | added | Marcus Müller | Let's rule out any candidates for simpler representations: combined with the calculation above is the proof. | |
| Jun 30, 2021 at 17:49 | comment | added | OverLordGoldDragon | If the "proof" is 1 and 2, it's fair evidence that someone could turn into a proof (but not me easily). I won't suppose you mean $g(y)$. | |
| Jun 30, 2021 at 17:43 | comment | added | Marcus Müller | simply the arguments so far haven't sufficiently shown it. That is not true, I've given mathematical proof. I'll stop arguing here – you clearly know what you want to hear, and you're not going to hear it from me, since it's wrong, sorry. | |
| Jun 30, 2021 at 17:42 | comment | added | OverLordGoldDragon | @AlexTP I can repeat your statement for any other DFT property. | |
| Jun 30, 2021 at 17:41 | comment | added | OverLordGoldDragon | I take your point. But it's not a pass to end the matter; whatever the relation is, it's probably complicated, but not necessarily useless, especially in discrete time where we seek error bounds that are well-revealed by infinite series. I'm keeping the question open for those willing to pursue further. | |
| Jun 30, 2021 at 17:39 | comment | added | OverLordGoldDragon | "If it exists, it's ugly and not useful" is a valid take, yes - simply the arguments so far haven't sufficiently shown it. I'll note that I haven't realized my plots' spikes aren't the sole non-zero components - meaning there's no clean discrete-time relation. If continuous FT is the only teller, it likely involves infinite series, potentially up to $2N$ of them, but if it's under a single double-sum... | |
| Jun 30, 2021 at 15:32 | comment | added | AlexTP | @OverLordGoldDragon if the operation you are looking for is a function, it equals to $g(\cdot)$. I don't know if there is a "meaningful" property that is not shared between two functions that equal. | |
| Jun 30, 2021 at 5:38 | comment | added | Marcus Müller | @OverLordGoldDragon no, the rest of the argument is not "it's hard to figure out"; I showed none of the kind of operations that would be considered useful are possible. Also, I reminded you of the truth that nonlinear operations make all parts of the signal interfere with each other, which also means it can't be simple. Are you sure that when you asked this, you did not already have an answer in mind, that you're now not willing to give up? | |
| Jun 30, 2021 at 2:27 | comment | added | OverLordGoldDragon | The $g(y)$ argument is tautological and can repeat for any other DFT property. Squaring is nonlinear and the relation is self-convolution, which is an integral. The rest of statements amount to "it's hard to figure out". Not convinced. | |
| Jun 29, 2021 at 22:19 | comment | added | Envidia | I like the part where, in mentioning non-linear operators like abs() to SP folks, there's a sigh of relief similar to when someone cancels plans that you didn't want to participate in the first place lol. | |
| Jun 29, 2021 at 22:02 | comment | added | Dan Boschen | Nice Marcus! +1 | |
| Jun 29, 2021 at 20:45 | comment | added | robert bristow-johnson | whatta autopsy. +1 | |
| Jun 29, 2021 at 20:15 | history | answered | Marcus Müller | CC BY-SA 4.0 |
