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Jun 1, 2021 at 12:00 history tweeted twitter.com/StackSignals/status/1399697244589379586
Jun 1, 2021 at 11:50 answer added Ben timeline score: 3
Jun 1, 2021 at 11:45 comment added Ben you should feed the q component to the PLL, not the "d" component.
Jun 1, 2021 at 5:18 comment added Steve @Ben Yes, I did. Based on the root locus design $K_p=460\,\mathrm{Hz/V}$ but the actually used $K_p=\frac{460}{\sqrt{2}\cdot 220}=1.478\,\mathrm{Hz/V}$.
Jun 1, 2021 at 1:55 comment added Ben Did you normalize the gain by dividing by the nominal voltage amplitude?
May 31, 2021 at 19:10 answer added Dan Boschen timeline score: 5
May 31, 2021 at 15:05 comment added Steve Continuous time derivation: $K_p=1.478\,\mathrm{Hz/V}, T_i=0.0043\,\mathrm{s}, K_i=\frac{K_p}{T_i}=343.72\,\mathrm{Hz/V}$. Sampling time: $T=50\,\mu s$. Discrete time simulation: $K_p=1.478\,\mathrm{Hz/V}, K_i=\frac{K_p\cdot T}{2\cdot T_i}=0.0086\,\mathrm{Hz/V}$.
May 31, 2021 at 13:49 comment added Dan Boschen What was the constant you came up with for $K_p$ from your continuous time derivation, and then what did you end up using in your discrete time simulation and what is your sampling rate?
May 31, 2021 at 11:08 comment added Steve Do I understand correctly or did you mean something else by the integration scaling?
May 31, 2021 at 6:19 comment added Steve @DanBoschen thank you for your reaction. As far as the integration gain I have been using this $K_i = \frac{K_p\cdot T}{2\cdot T_i}$, where $T$ is the sampling interval.
May 31, 2021 at 2:32 comment added Dan Boschen I didn't have time to read through this all yet Steve but just wanted to check if you properly scaled your integration by T as the sampling interval? When this happens to me it is usually because of this.
May 30, 2021 at 13:58 history asked Steve CC BY-SA 4.0