Timeline for Impulse response for an LTI system
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18 events
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Apr 19, 2021 at 14:52 | vote | accept | Brain Damage | ||
Apr 19, 2021 at 0:02 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 22:45 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 22:33 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 21:45 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 21:35 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 21:25 | comment | added | Fat32 | @robertbristow-johnson see the edit please | |
Apr 18, 2021 at 21:25 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 20:48 | comment | added | robert bristow-johnson | it is clear with the single rect pulse going in and the triangle pulse coming out. | |
Apr 18, 2021 at 20:47 | comment | added | robert bristow-johnson | well, at least it's not a strictly stable LTI. maybe if there were an infinite number of poles on the unit circle to generate the non-decaying triangle wave. | |
Apr 18, 2021 at 20:47 | comment | added | Fat32 | @robertbristow-johnson I do not claim that the system is LTI, it's stated in the problem. I have not investigated if the input-output pair actually violates the LTI principle as you have stated. Let me look at it, if indeed there exists frequencies at the output that does not exist at the input; then I will notify you. | |
Apr 18, 2021 at 20:44 | comment | added | robert bristow-johnson | i am refraining from a -1. but the answer is wrong. | |
Apr 18, 2021 at 20:41 | comment | added | robert bristow-johnson | Actually, there are frequencies of the input spectrum with zero amplitude that somehow get multiplied by the frequency response and become non-zero. so this is not a possible LTI system because the output contains frequency components that do not exist in the input. | |
Apr 18, 2021 at 20:36 | comment | added | robert bristow-johnson | okay, i'm wrong. i see how it could be LTI where a $s(t)=\Pi(t)$ is the input and a single $g(t)=\Lambda(2t)$ is the output. there might be a zero divided by zero issue where the $S(f)=\operatorname{sinc}(f)$ spectrum of the input becomes a $G(f)=\frac12 \operatorname{sinc}^2(\frac{f}2)$ spectrum in the output. gonna be a very strange frequency response. I cannot see how the length of the output (one unit of time) can be the same as the length of the input (also one unit of time). how does the LTI system not ring out a little longer? | |
Apr 18, 2021 at 20:12 | comment | added | robert bristow-johnson | Fat, once you look at Aufgabe 1.1 a), you can tell that the particular system is not linear at all. it is a multiplier with $g(t)$ as the output, the periodic triangle wave is one input, and $s(t)$ is the other input. | |
Apr 18, 2021 at 19:05 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 18:43 | history | edited | Fat32 | CC BY-SA 4.0 |
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Apr 18, 2021 at 18:37 | history | answered | Fat32 | CC BY-SA 4.0 |