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I'm trying to change the pitch of a signal using a Fourier Transform (FFT) followed by an Inverse Fourier Transform (IFFT).

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but halvesreduces the volume by one half. This seems to be corrected by doubling the magnitude.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

I'm trying to change the pitch of a signal using a Fourier Transform (FFT) followed by an Inverse Fourier Transform (IFFT).

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but halves the volume. This seems to be corrected by doubling the magnitude.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

I'm trying to change the pitch of a signal using a Fourier Transform (FFT) followed by an Inverse Fourier Transform (IFFT).

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but reduces the volume by one half. This seems to be corrected by doubling the magnitude.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

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I'm trying to change the pitch of a signal using a Fourier Transform (FFT) followed by an Inverse Fourier Transform (IFFT).

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but reduceshalves the volume. ItThis seems to be corrected by multiplyingdoubling the magnitude by $2$.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

I'm trying to change the pitch of a signal using a Fourier Transform followed by an Inverse Fourier Transform.

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but reduces the volume. It seems to be corrected by multiplying the magnitude by $2$.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

I'm trying to change the pitch of a signal using a Fourier Transform (FFT) followed by an Inverse Fourier Transform (IFFT).

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but halves the volume. This seems to be corrected by doubling the magnitude.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

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I'm trying to change the pitch of a signal using a Fourier Transform followed by an Inverse Fourier Transform.

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but reduces the volume. ThisIt seems to be corrected by multiplying the magnitude by $2$.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

I'm trying to change the pitch of a signal using a Fourier Transform followed by an Inverse Fourier Transform.

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but reduces the volume. This seems to be corrected by multiplying the magnitude by $2$.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

I'm trying to change the pitch of a signal using a Fourier Transform followed by an Inverse Fourier Transform.

I've found many examples, some of which zero out the right half of the real and imaginary bins before changing the pitch. For example, if the signal was $8192$ bins, the real and imaginary parts from $4096$ to $8192$ are set to $0$. This seems to make the math for pitch changing easier, but reduces the volume. It seems to be corrected by multiplying the magnitude by $2$.

I'm wondering what effect wiping the right half of the bins has on the final signal, apart from reducing the volume. I am confused why these bins exist if they can be wiped without affecting the final signal too much.

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