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May 16, 2020 at 20:24 vote accept StarBucK
May 16, 2020 at 17:35 comment added Matt L. $$y(0)=\int x(\tau)\delta'(-\tau)d\tau=-\int x(\tau)\delta'(\tau)d\tau=\int x'(\tau)\delta(\tau)d\tau=x'(0)$$
May 16, 2020 at 17:34 comment added Matt L. @StarBucK: Your equation is correct, but it doesn't imply a minus sign in Eq. (4). Note that $\delta'(t)$ is an odd function.
May 16, 2020 at 17:27 comment added StarBucK Thank you for your answer. However isn't $<\delta',x> = -<\delta,x'>$ ? Thus you should have a minus in your last equation ?
May 16, 2020 at 17:24 history answered Matt L. CC BY-SA 4.0