$\sigma$ is associated with attenuation in "Control Theory" and there Laplace is more suitable than Fourier. $\sigma=0$ the transformation becomes Fourier.

• There is unilateral and bilateral Laplace transformation. @Matt L have explained somewhere here the strong relationship between Laplace and Fourier.

$\sigma$ is associated with attenuation in "Control Theory" and there Laplace is more suitable than Fourier. $\sigma=0$ the transformation becomes Fourier.

• There is unilateral and bilateral Laplace transformation & periodic signals and Laplace transform. @Matt L have explained somewhere here the strong relationship between Laplace and Fourier.

$\sigma$ is associated with attenuation in "Control Theory" and there Laplace is more suitable than Fourier. $\sigma=0$ the transformation becomes Fourier.

• I am not a math guy. @Matt L have explained the strong relation between Laplace and Fourier.

$\sigma$ is associated with attenuation in "Control Theory" and there Laplace is more suitable than Fourier. $\sigma=0$ the transformation becomes Fourier.

• There is unilateral and bilateral Laplace transformation. @Matt L have explained somewhere here the strong relationship between Laplace and Fourier.