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robert bristow-johnson
robert bristow-johnson
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When there is an exact integer number of cycles of a periodic signal in the FFT aperture, there is no spectral leakage.

I said this beforeI said this before but the DFT maps a periodic sequence of length $N$ to another periodic sequence of length $N$ and the iDFT maps it back. That is fundamentally what the Discrete Fourier Transform does.

More elaboration here and here.

When there is an exact integer number of cycles of a periodic signal in the FFT aperture, there is no spectral leakage.

I said this before but the DFT maps a periodic sequence of length $N$ to another periodic sequence of length $N$ and the iDFT maps it back. That is fundamentally what the Discrete Fourier Transform does.

More elaboration here and here.

When there is an exact integer number of cycles of a periodic signal in the FFT aperture, there is no spectral leakage.

I said this before but the DFT maps a periodic sequence of length $N$ to another periodic sequence of length $N$ and the iDFT maps it back. That is fundamentally what the Discrete Fourier Transform does.

More elaboration here and here.

Source Link
robert bristow-johnson
robert bristow-johnson
  • 21.5k
  • 4
  • 39
  • 78

When there is an exact integer number of cycles of a periodic signal in the FFT aperture, there is no spectral leakage.

I said this before but the DFT maps a periodic sequence of length $N$ to another periodic sequence of length $N$ and the iDFT maps it back. That is fundamentally what the Discrete Fourier Transform does.

More elaboration here and here.