Timeline for Phase of the DFT
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 23, 2023 at 12:27 | vote | accept | BullWebster | ||
| Sep 9, 2019 at 16:25 | comment | added | Matt L. | @BullWebster: Just use $(1-e^{-j\phi})=e^{-j\phi /2}(e^{j\phi/2}-e^{-j\phi/2})=e^{-j\phi /2} 2j\sin(\phi/2)$. | |
| Sep 9, 2019 at 14:57 | comment | added | BullWebster | Thanks for your reply. I was missing the windowing. By using the geometric sum formula, I arrived to $(1 - e ^ {j 2 \pi N (f_0 + k / N)}) / (1 - e ^ {j 2 \pi (f_0 + k / N)})$. How did you get the expression in (2)? | |
| Aug 29, 2019 at 11:00 | history | answered | Matt L. | CC BY-SA 4.0 |