Timeline for Understanding the phase in DFT
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 17, 2019 at 21:17 | comment | added | Cedron Dawg | @Machupicchu Yes. Each bin corresponds to a component with with a frequency of its bin index in cycles per frame. I recommend you read the following of my articles in this order: dsprelated.com/showarticle/754.php dsprelated.com/showarticle/1238.php dsprelated.com/showarticle/768.php dsprelated.com/showarticle/1284.php Then follow the links if needed. | |
| Jul 17, 2019 at 21:03 | comment | added | SheppLogan | Ok thanks. In fact i think using the trig circle can help me too. (And the matrix vector interpretation of the DFT (1D dft) each component of the vector Wx (given W is dft matrix, x is signal), would be a complex number z = rexp(iphi) and so r is magnitude (abs(z)) and phi is angle(z) so considering the phase, which i m interested in, phi would then be (here for just 1 component) the amount of phase shift from.the pure real cosine of the given frequency k for that z component ... if you see what i mean?Correct ? | |
| Jul 17, 2019 at 20:57 | vote | accept | SheppLogan | ||
| Jul 17, 2019 at 20:33 | comment | added | Cedron Dawg | @Machupicchu You're welcome. The last blurb should help you out. I'm leaving for a while. This might help too: dsp.stackexchange.com/questions/59305/… | |
| Jul 17, 2019 at 20:31 | history | edited | Cedron Dawg | CC BY-SA 4.0 |
added 204 characters in body
|
| Jul 17, 2019 at 20:25 | comment | added | SheppLogan | Thanks for your effort. However, there is still something that bothers me. I m not sure i m able to formulate it in a meaningful way but roughly: ok i understand with your formula that a phase shift in cos of freq f is related to a weighted sum of sine and cos. But how does that explain that we need/use the phase part in Fourier transform? The imaginary part which is not the same.as the phase which is actually arctan(im/re)..? | |
| Jul 17, 2019 at 20:09 | history | edited | Cedron Dawg | CC BY-SA 4.0 |
added 21 characters in body
|
| Jul 17, 2019 at 19:46 | history | edited | Cedron Dawg | CC BY-SA 4.0 |
added 1018 characters in body
|
| Jul 17, 2019 at 19:33 | comment | added | SheppLogan | Thanks for the answer. However, I am looking for a more intuitive understanding of what the phase angle really means , e.g., what does it "represent as a shift" , e.g. the values in angle(x), represent a shift w.r.t ...what? | |
| Jul 17, 2019 at 19:13 | history | edited | Cedron Dawg | CC BY-SA 4.0 |
added 41 characters in body
|
| Jul 17, 2019 at 14:55 | history | answered | Cedron Dawg | CC BY-SA 4.0 |