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Laurent Duval
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With original image $o$ fixed, the higher, the better. If PSRN($o,d$) is bigger than PSRNPSNR($o,n$), you can claim an improvement in the decibel measure. It is difficult to interpret PSRN($d,n$), sinceyousince you compare two more-or-less noisy data.

Is PSRNPSNR a good measure of subjective image quality remains an open question.

With original image $o$ fixed, the higher, the better. If PSRN($o,d$) is bigger than PSRN($o,n$), you can claim an improvement in the decibel measure. It is difficult to interpret PSRN($d,n$), sinceyou compare two more-or-less noisy data.

Is PSRN a good measure of subjective image quality remains an open question.

With original image $o$ fixed, the higher, the better. If PSRN($o,d$) is bigger than PSNR($o,n$), you can claim an improvement in the decibel measure. It is difficult to interpret PSRN($d,n$), since you compare two more-or-less noisy data.

Is PSNR a good measure of subjective image quality remains an open question.

Source Link
Laurent Duval
  • 32.3k
  • 3
  • 35
  • 105

With original image $o$ fixed, the higher, the better. If PSRN($o,d$) is bigger than PSRN($o,n$), you can claim an improvement in the decibel measure. It is difficult to interpret PSRN($d,n$), sinceyou compare two more-or-less noisy data.

Is PSRN a good measure of subjective image quality remains an open question.