Timeline for Calculating Data Rate using Bandwidth, Transmission Power, Noise Power Spectrum Density and Channel Gain
Current License: CC BY-SA 4.0
18 events
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May 20, 2019 at 17:26 | comment | added | Ben | @BlackMath one of my main references for calculating data rate is the paper: ieeexplore.ieee.org/document/7842160 | |
May 20, 2019 at 16:36 | vote | accept | Ben | ||
May 20, 2019 at 13:21 | comment | added | BlackMath | Do you have any reference on what you are trying to do? I understand that you are not a telecomm. engineer, and may not have interpreted things correctly. | |
May 20, 2019 at 11:12 | answer | added | Florian | timeline score: 3 | |
May 20, 2019 at 9:11 | comment | added | Ben | @Florian I don't need to have very precise value for this part of my research. As you said, having an upper bound is enough for me, but currently, the value in the logarithm has gotten negative. Hence, I don't whether I should convert the unit of my parameters or not. For instance, should transmission power be in dBm or it should be in watt? Also, N0 which is in dBm/Hz. | |
May 20, 2019 at 8:44 | comment | added | Ben | @BlackMath I edited the question and changed the name of the formula, but I don't have channel statistics. With this formula, I should calculate the data rate. | |
May 20, 2019 at 8:41 | history | edited | Ben | CC BY-SA 4.0 |
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May 20, 2019 at 7:00 | comment | added | Florian | With the given quantities you can compute a (distance-dependent) average SNR at the receiver. With the Shannon formula you could get a value for what would be the maximum achievable data rate given that there were no fading and you had perfect link adaptation (which you IoT devices won't have, they'll very likely use a simple modulation scheme). It's an upper bound really. That said, it is not too uncommon to use it for some initial analysis and network planning. It depends a bit on what you want to use the value for. | |
May 20, 2019 at 1:33 | comment | added | BlackMath | What is of interest usually is the channel capacity. Since the channel is wireless, you would need to find the ergodic Shannon capacity, which is the capacity averaged over all channel realizations. If you know the channel statistics, then just plug it in this equation $$\int_0^{\infty}C(h)\,f_h(h)\,dh$$ where $C(h)$ is the capacity for a given realization, and $f_h(h)$ is the pdf of the channel coefficient $h$. | |
May 19, 2019 at 20:00 | comment | added | MBaz | As I said in my first comment, you need the required SNR at the receiver (or the tolerable error rate), and the constellation. You will also need the pulse shape and the statistics of $H$. | |
May 19, 2019 at 19:27 | comment | added | Ben | @MBaz Do the missed data relate to channel gain? | |
May 19, 2019 at 19:13 | comment | added | MBaz | @BenyaminT Note that a channel does not have a rate; it has a capacity. A communications system achieves a fraction of that capacity. As I said, you don't have enough data to calculate a rate. | |
May 19, 2019 at 19:04 | comment | added | Ben | @BlackMath I need to calculate a wireless channel data rate. | |
May 19, 2019 at 18:10 | comment | added | BlackMath | The Shannon capacity is the maximum data rate you can transmit over a channel. What is the type of the channel you are considering. Is it wireless or wired? | |
May 19, 2019 at 17:37 | comment | added | Ben | @MBaz I've seen on dsp.stackexchange.com/questions/58420 and some papers that the name of this formula is Shannon, though it doesn't matter to me :). No, this is a part of my research in which I need to calculate the achievable transmit rate of Mobile Devices. | |
May 19, 2019 at 16:21 | comment | added | MBaz | You don't have enough information to calculate the data rate. You're missing the required SNR at the receiver, and the constellation. Also, Shannon's theorem is irrelevant here since you don't seem to be using any coding. I have seen problems like this in some textbooks, though; is this a homework problem? | |
May 19, 2019 at 16:15 | review | First posts | |||
May 19, 2019 at 16:16 | |||||
May 19, 2019 at 16:15 | history | asked | Ben | CC BY-SA 4.0 |