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Aug 20, 2019 at 11:18 comment added Tom Wenseleers Well the function I am using, hexp(((x-u)^2)/(-2*(w^2))), has maximum h and the w is the SD of a gaussian density distribution. But it is not strictly speaking a gaussian density distribution, as that would have 1/sqrt(2*piw^2), instead of h...
Aug 20, 2019 at 5:39 comment added Royi I have zero knowledge in R. What I don't understand is how Gaussian Curve can have width which is independent of height. If you scale $ {e}^{-\frac{ {x}^{2} }{2}} $ its width changes. I assume width has something to do with the STD.
Jan 25, 2019 at 0:00 history tweeted twitter.com/StackSignals/status/1088587394654314502
Jan 17, 2019 at 22:54 history edited Tom Wenseleers CC BY-SA 4.0
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Jan 10, 2019 at 14:38 comment added Peter K. Cute question! My go-to for this sort of thing is usually a LMS algorithm... but it wouldn't be fast. And there's a problem of deciding how many gaussians there really are. :-)
Jan 10, 2019 at 14:31 history edited Tom Wenseleers CC BY-SA 4.0
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Jan 10, 2019 at 14:29 comment added Tom Wenseleers Just taking the minimum observed peak width if one would focus on the smallest peak resolved to baseline btw wouldn't work since in my real signals I also have occasional noisy spikes... And there could also be cases where the signal is nowhere resolved to baseline because of the high nr of overlapping peaks...
Jan 10, 2019 at 14:25 comment added Tom Wenseleers Ideally yes - though the recovery of individual peaks is not that important, it's more that I need a decent estimate of the average peak width over this whole window, taking into account that peaks can of course be superimposed and can overlap. The fact that I assume that all peaks are identically shaped should help with the identifiability of the problem though...
Jan 10, 2019 at 14:22 comment added A_A What about those peaks that are very very close to each other? Do they need to be resolved individually?
Jan 10, 2019 at 14:21 history edited Tom Wenseleers CC BY-SA 4.0
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Jan 10, 2019 at 14:16 comment added Tom Wenseleers It would be OK to assume the peaks were Gaussian though, even though their width and amplitudes are unknown... The peak locations and amplitudes are not important for my purposes - it's just the average width I need...
Jan 10, 2019 at 14:15 history edited Tom Wenseleers CC BY-SA 4.0
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Jan 10, 2019 at 14:12 comment added Tom Wenseleers Well the problem here would be that the Gaussian is not known, so I would like to estimate the most likely peak shape given that the signal that I measuring is a superposition of many such peaks with different amplitude - I've added some R code to make my question clearer...
Jan 10, 2019 at 13:57 comment added A_A It really depends on what you are after, you could do Kernel Density Estimation or even Deconvolution with the known gaussian. Do you think you could share a bit more about the problem?
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Jan 10, 2019 at 13:45 history asked Tom Wenseleers CC BY-SA 4.0