Return to Answer

The poles in the equation are Z=1.5,0.8;hence to be two sided the roc is $0.8<=z<=1.5$ so the 0.8 term is right sided and 1.5 term is left sided let us do partial fractions now $ X(Z)=1+\frac{1.5-0.85z^{-1}} {(1-0.8z^{-1})(1-1.5z^{-1})} $ after doing some maths i got $x(n)=delta(n)-0.5(0.8)^nu(n)-2(1.5)^nu(-n-1)$ so x(-2)=-0.88888,x(-1)=-1.3333,x(0)=0.5,x(1)=-0.4,x(2)=-0.32.so am I correct?

The poles in the equation are Z=1.5,0.8;hence to be two sided the roc is $0.8<=z<=1.5$ so the 0.8 term is right sided and 1.5 term is left sided let us do partial fractions now $ X(Z)=1+\frac{1.5-0.85z^{-1}} {(1-0.8z^{-1})(1-1.5z^{-1})} $ after doing some maths i got $x(n)=\delta(n)-0.5(0.8)^nu(n)-2(1.5)^nu(-n-1)$ so x(-2)=-0.88888,x(-1)=-1.3333,x(0)=0.5,x(1)=-0.4,x(2)=-0.32.

The poles in the equation are Z=1.5,0.8;hence to be two sided the roc is $0.8<=z<=1.5$ so the 0.8 term is right sided and 1.5 term is left sided let us do partial fractions now $ X(Z)=1+\frac{1.5-0.85z^{-1}} {(1-0.8z^{-1})(1-1.5z^{-1})} $ after doing some maths i got $x(n)=delta(n)-0.5(0.8)^nu(n)-2(1.5)^nu(-n+1)$ so x(-2)=-0.88888,x(-1)=-1.3333,x(0)=0.5,x(1)=-0.4,x(2)=-0.32.so am I correct?

The poles in the equation are Z=1.5,0.8;hence to be two sided the roc is $0.8<=z<=1.5$ so the 0.8 term is right sided and 1.5 term is left sided let us do partial fractions now $ X(Z)=1+\frac{1.5-0.85z^{-1}} {(1-0.8z^{-1})(1-1.5z^{-1})} $ after doing some maths i got $x(n)=delta(n)-0.5(0.8)^nu(n)-2(1.5)^nu(-n-1)$ so x(-2)=-0.88888,x(-1)=-1.3333,x(0)=0.5,x(1)=-0.4,x(2)=-0.32.so am I correct?

The poles in the equation are Z=1.5,0.8;hence to be two sided the roc is $0.8<=z<=1.5$ so the 0.8 term is right sided and 1.5 term is left sided let us do partial fractions now $ X(Z)=1+\frac{1.5-0.85z^{-1}} {(1-0.8z^{-1})(1-1.5z^{-1})} $ after doing some maths i got $x(n)=delta(n)-0.5(0.8)^nu(n)-2(1.5)^nu(-n+1)$ so x(-2)=-0.88888,x(-1)=-1.3333,x(0)=0.5,x(1)=0.4,x(2)0.32.so am I correct?

The poles in the equation are Z=1.5,0.8;hence to be two sided the roc is $0.8<=z<=1.5$ so the 0.8 term is right sided and 1.5 term is left sided let us do partial fractions now $ X(Z)=1+\frac{1.5-0.85z^{-1}} {(1-0.8z^{-1})(1-1.5z^{-1})} $ after doing some maths i got $x(n)=delta(n)-0.5(0.8)^nu(n)-2(1.5)^nu(-n+1)$ so x(-2)=-0.88888,x(-1)=-1.3333,x(0)=0.5,x(1)=-0.4,x(2)=-0.32.so am I correct?