Timeline for Parseval's Theorm and Effective Bandwidth
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Mar 8, 2018 at 19:17 | comment | added | EE_13 | @MattL. a reference for where you got the definition of effective bandwidth for a bandpass signal would be a huge help to me | |
| Mar 8, 2018 at 19:11 | history | edited | EE_13 | CC BY-SA 3.0 |
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| Mar 8, 2018 at 19:10 | comment | added | EE_13 | @MBaz if you use the derivative property of the FT as well as the partial derivative of the signal then you can derive this from Parseval's theorem in two steps. See page 339 of Whalen's "Detection of Signals in Noise" for a direct reference. | |
| Mar 8, 2018 at 19:09 | comment | added | EE_13 | @MattL. I mean that shifting the carrier frequency of a pulse does not change the effective bandwidth as your answer states. However in the example I posted above this seems to be untrue and that is where my confusion lies. thanks for taking the time to look at this! | |
| Mar 8, 2018 at 8:12 | comment | added | Matt L. | I'm not sure I understand your question. In the accepted answer to the question you linked to, I explained that the definition of RMS bandwidth depends on the center frequency. So you can't use the same formula for defining the RMS bandwidth of $s(t)$ (band pass signal) and $x(t)$ (low pass signal) as you did. | |
| Mar 7, 2018 at 23:34 | comment | added | MBaz | I'm unfamiliar with that form of Parseval's theorem... do you have a reference? | |
| Mar 7, 2018 at 23:32 | history | edited | MBaz | CC BY-SA 3.0 |
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| Mar 7, 2018 at 23:24 | review | First posts | |||
| Mar 7, 2018 at 23:40 | |||||
| Mar 7, 2018 at 23:22 | history | asked | EE_13 | CC BY-SA 3.0 |