Timeline for IDTFT of $\sum_{k=-\infty}^{+\infty}(u(\Omega+\pi)+u(\Omega+\frac{\pi}{4})-u(\Omega-\frac{\pi}{4})-u(\Omega-\pi))\star \delta(\Omega-2k\pi)$
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Jan 31, 2018 at 18:00 | vote | accept | CommunityBot | ||
| Jan 31, 2018 at 17:56 | comment | added | Tendero | @Jason I've added some useful information to the answer. | |
| Jan 31, 2018 at 17:56 | history | edited | Tendero | CC BY-SA 3.0 |
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| Jan 31, 2018 at 17:45 | comment | added | Tendero | @Jason Indeed, and in fact $\frac{\sin(\pi n)}{\pi n} = \delta(n)$. Its transform is $$\sum_{k=-\infty}^{+\infty}\left(u(\Omega+\pi)-u(\Omega-\pi)\right)\star \delta(\Omega-2k\pi)$$ If you watch closely, that is the same as writing $1 \ \forall \Omega$, which corresponds to the DTFT of the delta. Thus the solution given in the answer is correct. | |
| Jan 31, 2018 at 17:39 | comment | added | user33199 | I don't think so... You know, $sin(\pi n) = 0$ for all $n$ since we are in natural numbers... | |
| Jan 31, 2018 at 17:30 | history | answered | Tendero | CC BY-SA 3.0 |