To begin you must write the output of filter as a convolution (readat first read a book on stochastic process or stochastic signal processing. it's better that we say we have a random process which it's first order distribution (PDF of the process at each instant of time) is independent of time and is a Gaussian with known mean and variance. Now we want to obtain the first order properties of filtered process.
Your new random variable which isTo begin we write the output of filter as a convolution. The output process at each instant of time is a linear combination (weighted average) of filter input process at different instant of time which all has the same Gaussian distribution, also we know linear combination of gaussian RV isvariables with Gaussian PDF leads to another gaussian RVvariable with Gaussian distribution. So the first order distribution of output must be a Gaussian.
Now taking expectation from both side of convolution, we see expectation of your new random variable (its mean) is DC responsefiltered process at each instant of yourtime becomes convolution of filter (whichresponse and the mean of input process which is usually 1) timesa constant over time, so it becomes the multiplication of input mean and the DC response of your old random variablefilter.
To To obtain the variance youof process around its mean, we have to subtractfind the expectation of squared difference of the process and its mean from fromor expectation of squared value of output minus the signal thensquare of it's mean. To relate the squared value of output to the input we could convolve itthe filterd signal with its reversed time version then taking expectation at time zero lag. At the end youwe see new RV variance is the variance of input times square of DC response of filter.
I have to say it was better to use random process instead of random variable.