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Aug 15, 2017 at 15:31 comment added Fat32 Start from time domain signal $x[n]$ and consider its DTFT $X(e^{j\omega})$ in the range $\omega=0$ to $\omega=2\pi$, now upsample $x[n]$ by say 2, this'll shrink the DTFT $X(e^{j\omega})$ by 2 towards $\omega=0$ and $\omega= 2\pi$. Hence leave the central region empty. When you simulate this in Frequency domain, therefore, you will stuff zeros to the central region. Note that it's DFT $X[k]$ that is practically utilized.
Aug 15, 2017 at 15:19 comment added user59419 Can you explain why in frequency domain zero should be added in the middle of signal and not to the end of the signal?
Aug 15, 2017 at 15:17 vote accept user59419
Aug 14, 2017 at 19:36 history edited Fat32 CC BY-SA 3.0
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Aug 14, 2017 at 19:31 history edited Fat32 CC BY-SA 3.0
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S Aug 14, 2017 at 19:28 history suggested Gilles CC BY-SA 3.0
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Aug 14, 2017 at 19:24 review Suggested edits
S Aug 14, 2017 at 19:28
Aug 14, 2017 at 10:56 history answered Fat32 CC BY-SA 3.0