Timeline for Hilbert Huang Transform: Negative value in instantaneous frequency
Current License: CC BY-SA 3.0
10 events
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| Jan 16, 2018 at 15:51 | comment | added | mac13k | Matlab recommends to calculate instant. freq. using phase accumulation and in the question here a different method was used which I believe is called homodyne discrimination. I can confirm that I'm having the same problem in Python: homodyne discrimination produces negative values of instant. freq., however phase accumulation (also recommended by SciPy docs) produces positive values. That of course when dealing with IMF-grade analytic signals as required by EMD. I hope someone eventually answers this question thoroughly... | |
| Jul 12, 2017 at 21:24 | comment | added | robert bristow-johnson |
well @PeterK., it would be useful to see both waveforms, side-by-side. because the difference equation (fin=) that the OP is using looks correct.
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| Jul 12, 2017 at 21:10 | comment | added | Peter K.♦ |
@robertbristow-johnson : They're using Matlab's hilbert function, but it's not clear to me what that will produce.
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| Jul 12, 2017 at 18:48 | comment | added | robert bristow-johnson | is the analytic signal computed correctly (can you show that code)? maybe you have $$ x[n] - j \hat{x}[n] $$ instead of $$ x[n] + j \hat{x}[n] $$. | |
| Jul 12, 2017 at 18:03 | comment | added | Peter K.♦ | Welcome to SE.DSP! Interesting question! Have you compared the way you're calculating the instantaneous frequency with the way Matlab suggests ? I'm wondering if there will be a difference. | |
| S Jul 12, 2017 at 17:53 | history | suggested | Gilles | CC BY-SA 3.0 |
improved formatting + additional tag
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| Jul 12, 2017 at 17:00 | review | Suggested edits | |||
| S Jul 12, 2017 at 17:53 | |||||
| Jul 12, 2017 at 12:22 | history | edited | Peter K.♦ | CC BY-SA 3.0 |
Minor formatting issue
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| Jul 12, 2017 at 10:33 | review | First posts | |||
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| Jul 12, 2017 at 10:30 | history | asked | user28357 | CC BY-SA 3.0 |