I'm having a hard time understanding an assignment that states:
Draw the complex spectrum of the sampled signal f$f(t)$ (tperiodic and continuous). Do this, by first calculating the Fourier transformation and sample it afterwards by multiplying with the impulse train.
(The given signal is periodic and continuous)
The way I understand it, I need to calculate $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) \end{equation*}$$$$\begin{equation*} \mathcal{F}\left[f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right] \end{equation*}$$ however the second sentence suggests this is the same as $$F(f(t)) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$$$\mathcal{F}[f(t)] \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$ however wikipediaHowever, Wikipedia says this is not the case and instead suggests $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) = F(f) *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta(t-\frac{k}{T}))\right] \end{equation*}$$$$\begin{equation*}\mathcal{F}\left[f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right] = \mathcal{F}[f(t)] *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta\left(t-\frac{k}{T}\right)\right] \end{equation*}$$ are maybe both formulas correct? and how do I draw a complex spectrum? is it 3D?