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I'm having a hard time understanding an assignment that states:

Draw the complex spectrum of the sampled signal f$f(t)$ (tperiodic and continuous). Do this, by first calculating the Fourier transformation and sample it afterwards by multiplying with the impulse train.

(The given signal is periodic and continuous)

The way I understand it, I need to calculate $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) \end{equation*}$$$$\begin{equation*} \mathcal{F}\left[f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right] \end{equation*}$$ however the second sentence suggests this is the same as $$F(f(t)) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$$$\mathcal{F}[f(t)] \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$ however wikipediaHowever, Wikipedia says this is not the case and instead suggests $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) = F(f) *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta(t-\frac{k}{T}))\right] \end{equation*}$$$$\begin{equation*}\mathcal{F}\left[f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right] = \mathcal{F}[f(t)] *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta\left(t-\frac{k}{T}\right)\right] \end{equation*}$$ are maybe both formulas correct? and how do I draw a complex spectrum? is it 3D?

I'm having a hard time understanding an assignment that states:

Draw the complex spectrum of the sampled signal f(t). Do this, by first calculating the Fourier transformation and sample it afterwards by multiplying with the impulse train.

(The given signal is periodic and continuous)

The way I understand it I need to calculate $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) \end{equation*}$$ however the second sentence suggests this is the same as $$F(f(t)) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$ however wikipedia says this is not the case and instead suggests $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) = F(f) *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta(t-\frac{k}{T}))\right] \end{equation*}$$ are maybe both formulas correct? and how do I draw a complex spectrum? is it 3D?

I'm having a hard time understanding an assignment that states:

Draw the complex spectrum of the sampled signal $f(t)$ (periodic and continuous). Do this, by first calculating the Fourier transformation and sample it afterwards by multiplying with the impulse train.

The way I understand it, I need to calculate $$\begin{equation*} \mathcal{F}\left[f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right] \end{equation*}$$ however the second sentence suggests this is the same as $$\mathcal{F}[f(t)] \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$ However, Wikipedia says this is not the case and instead suggests $$\begin{equation*}\mathcal{F}\left[f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right] = \mathcal{F}[f(t)] *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta\left(t-\frac{k}{T}\right)\right] \end{equation*}$$ are maybe both formulas correct? and how do I draw a complex spectrum? is it 3D?

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Is sampling a Fourier transformed signal and fourier transforming a sampled signal the same?

I'm having a hard time understanding an assignment that states:

Draw the complex spectrum of the sampled signal f(t). Do this, by first calculating the Fourier transformation and sample it afterwards by multiplying with the impulse train.

(The given signal is periodic and continuous)

The way I understand it I need to calculate $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) \end{equation*}$$ however the second sentence suggests this is the same as $$F(f(t)) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT) $$ however wikipedia says this is not the case and instead suggests $$\begin{equation*}F\left(f(t) \cdot \sum_{k=-\infty}^{\infty}\delta(t-kT)\right) = F(f) *\left[\frac{1}{T} \cdot \sum_{k=-\infty}^{\infty}\delta(t-\frac{k}{T}))\right] \end{equation*}$$ are maybe both formulas correct? and how do I draw a complex spectrum? is it 3D?