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Dec 14, 2016 at 2:50 comment added Dilip Sarwate Perhaps the only cases when your conjectured result $C = C_1C_2$ is true is when both channels are noiseless ($C_1 = C_2 = 1 \implies C = 1$) or at least one channel has zero capacity in which case $C = 0 = C_1C_2$.
Dec 13, 2016 at 2:20 vote accept Amin
Dec 12, 2016 at 18:09 comment added Laurent Duval Adding "channel" to BSC is a bit redundant. Could you expand the acronym at least once, and provided more context on their transition probabilities?
Dec 12, 2016 at 17:37 answer added Maximilian Matthé timeline score: 3
Dec 12, 2016 at 17:29 review Low quality posts
Dec 12, 2016 at 18:09
Dec 12, 2016 at 17:09 history asked Amin CC BY-SA 3.0