Skip to main content
I think `` makes more sense than $$ in this case.
Source Link
MBaz
  • 15.4k
  • 9
  • 32
  • 46

I think you want to take the "central" part of the convolution. Convolution will give a signal that has $length(c) = length(a) + length(b) - 1$length(c) = length(a) + length(b) - 1. If you have Matlab or Octave, there is an option when using the convolution function to just take the central part.

I think you want to take the "central" part of the convolution. Convolution will give a signal that has $length(c) = length(a) + length(b) - 1$. If you have Matlab or Octave, there is an option when using the convolution function to just take the central part.

I think you want to take the "central" part of the convolution. Convolution will give a signal that has length(c) = length(a) + length(b) - 1. If you have Matlab or Octave, there is an option when using the convolution function to just take the central part.

Source Link
soultrane
  • 241
  • 1
  • 8

I think you want to take the "central" part of the convolution. Convolution will give a signal that has $length(c) = length(a) + length(b) - 1$. If you have Matlab or Octave, there is an option when using the convolution function to just take the central part.