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robert bristow-johnson
robert bristow-johnson
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DTFT is the Z-transform at the unit circle. So if $Z=re^{j\omega}$$z=re^{j\omega}$ then for DTFT $r = 1$.

i.e If you have the Z-transform of a signal then plug-in $e^{j\omega}$ for every $Z$$z$

DTFT is the Z-transform at the unit circle. So if $Z=re^{j\omega}$ then for DTFT $r = 1$.

i.e If you have the Z-transform of a signal then plug-in $e^{j\omega}$ for every $Z$

DTFT is the Z-transform at the unit circle. So if $z=re^{j\omega}$ then for DTFT $r = 1$.

i.e If you have the Z-transform of a signal then plug-in $e^{j\omega}$ for every $z$

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usfmohy
usfmohy
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DTFT is the Z-transform at the unit circle. So if $Z=re^{j\omega}$ then for DTFT $r = 1$.

i.e If you have the Z-transform of a signal then plug-in $e^{j\omega}$ for every $Z$