Timeline for Why should the cut off frequency and the transition bandwidth (BW) be expressed as a fraction of sampling rate?
Current License: CC BY-SA 3.0
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| when toggle format | what | by | license | comment | |
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| Feb 24, 2015 at 5:25 | vote | accept | PsychedGuy | ||
| Feb 21, 2015 at 6:36 | comment | added | PsychedGuy | I just read about the sampling theorem and Nyquist rate/frequency and correlated with your example. So basically, we consider the normalized sampling rate to be 1 and from Nyquist theorem the input signal must contain frequencies below one-half of the sampling rate i.e. 0.5. So, if we have an input signal with a frequency of 200Hz or 200cycles/sec, then the proper sampling rate for this signal is 400 sps or 400 Hz, thus satisfying 200/400 = 0.5, and for 200/600 = 0.33.This is what I understood, Pl correct me if wrong. Thanks! | |
| Feb 20, 2015 at 15:25 | history | answered | David | CC BY-SA 3.0 |