Timeline for What does the normalization step of the Haar wavelet transform represent?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Apr 2, 2015 at 13:50 | history | edited | endolith | CC BY-SA 3.0 |
typo
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| Jan 17, 2014 at 16:06 | comment | added | MSalters | Projection on an incomplete basis would lose energy, trivially: the projection is no longer identical to the original, but has lost all information(energy) orthogonal to the incomplete basis. | |
| Mar 17, 2012 at 21:01 | comment | added | Spacey | @bobobobo Yup! You got it. Now I seem to remember that a loss of energy can in fact be possible with some transforms, (and this would also be conceivable), but I cannot recall any such cases at the moment. | |
| Mar 17, 2012 at 20:57 | comment | added | bobobobo | Ok, this makes sense. If you try it with an array of numbers, eg [ 2 1 3 4 9 7 0 4 ] -> 1 step sum/diff -> [ 1.5 3.5 8 2 | .5 -.5 1 -2 ]. The squared norm of the first signal is 176, the second one is 88. Multiplying the second signal by √2 makes it's squared norm 176 as well. | |
| Mar 17, 2012 at 20:23 | vote | accept | bobobobo | ||
| Mar 16, 2012 at 17:21 | history | answered | Spacey | CC BY-SA 3.0 |