Timeline for Why are FIR filters still stable even though they contain poles?
Current License: CC BY-SA 3.0
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| Jan 9, 2014 at 9:14 | comment | added | Tom Kealy | @robertbristow-johnson sorry, yes. I was thinking of a generating function. However, I don't think the answer above changes under the action of $z$ -> $z^{-1}$. | |
| Jan 8, 2014 at 16:14 | comment | added | robert bristow-johnson | Tom, i think the Z-transform of a realizable FIR contain only negative powers of $z$. well, okay, only non-positive powers of $z$. | |
| Jan 8, 2014 at 12:23 | history | answered | Tom Kealy | CC BY-SA 3.0 |