# Tagged Questions

The Z-transform converts a discrete time-domain signal, which is a sequence of real or complex numbers, into a complex frequency-domain representation.

27 views

34 views

### Efficient computation of Chirp Z Transform

Chirp Z Transform (1, 2, 3) is more powerful than zooming techniques (I use it to actually trace non-stationary chirp signals) and very usable in signal processing, but it's flexibility comes at price ...
24 views

76 views

### Is the below filter linear phase

$$h(t) = \frac{1}{1 + t^2}$$ and is it IIR or FIR filter. I tried finding the Laplace transform of this filter to get the data flow diagram with 5 taps and T=2s, however, I am unable to solve this. ...
75 views

### Inverse Z-transform with complex conjugate poles

I was computing an inverse z-transform here, and I am facing some problems. So, the z-transform is: $$X(z) = \frac{2+3z^{-1}}{1 - z^{-1} + 0.81z^{-2}} , |z| > 0.9$$ I found the following poles:...
63 views

After studying z transform from different books and literature on internet I want to ask few which makes me confuse. a) From the Discrete Time Fourier Transform we have drive equation for z ...
120 views

### What does 'z' in Z-transform represent ? Is it frequency or something else?

my question is about the Z- transform. My first question is what the title says. What does 'Z' in Z-transform represent ? Say in Fourier transform, 'w' (omega) represents frequency ? From Fourier ...
32 views

### What is the right way to calculate the inverse Z-transform of $zX(z^{-1})$

say the signal $x(n)$ has the z transform $X(z)$ and there is signal $x_1(n)$ that $X_1(z)=zX(z^{-1})$ I tried 2 different approach to get the relationship between $x(n)$ and $x_1(n)$ and the ...
First of all, thank you all for your answers. I know the z transform for $$x(n)=3^n \space ; \space n\geqslant 3$$ or rather $$x(n)= 3^n u(n-3)$$\begin{align}X(z)&=\sum_{n=-\infty}^{\... 1answer 30 views ### Phase response for conjugate zeros If a second order system has 2 poles/zeros that are conjugate symmetric, how does this affect the phase response? I know that if there are 4 zeros/poles that are conjugate reciprocals, then it is a ... 2answers 33 views ### the ROC of a Z-transform for shifted signal I have got two different answers for the ROC of the signal. In that PIC, I have solved it in 2 methods, but I'm getting different answer. Which one is correct? Also please explain how to find the ROC ... 3answers 78 views ### The right way to approach z transform? I am a student learning dsp. I like the subject. I could understand the discrete time signals. When I move into z transform. I could not understand it. Z transform is the mapping from discrete ... 1answer 91 views ### What does z-transform imply? As z tranform is the transformation of discrete time signals into complex frequency domian. What do you get out of complex Stuff. As wikipedia calls it complex frequency domain. Why do you need it ? ... 1answer 41 views ### System Stability: Can we derive stability of a discrete system (Frequency domain, Z-transform) by applying analogous methods? So given some analogue system function in the complex s-domain. Can we perform a stability analysis in the s-domain, before actually transfer it into the z-domain? So in other words analysis in ... 0answers 33 views ### Non-causal z transform in MATLAB? In MATLAB, a causal z transfer function can be specified with filt(). Is it possible to specify a transfer function with acausal terms (positive exponent on z)? 1answer 56 views ### Z-transform of an FIR filter QUESTION Compute the Z-transform of y[n] = x[n] + 2x[n-1]. and find the poles and zeros. I just bombed an interview where I couldn't do this (because I have no grounding in fundamentals and have ... 0answers 104 views ### Inverse z transform - Pair of complex conjugate poles How can I perform the inverse z-transform on the following H(z) to be able to calculate a real-valued impulse response h[n]? H(z)=\frac{z^2}{z^2+0.8\sqrt{2}z+0.64}  My idea was to find an ...
In Z-Transform, For a real signal, $x(n)$ =$x^*(n)$ . Taking Z-transform on both sides, $X(z)$=$X^*(z^*)$ , which gives certain pole/zero condition similarly for a purely imaginary signal ...