For the difference equation below:
$y(k)=1/2{x(k)+x(k-1)}$
How i can find he z-domain transfer function?
Thanks.
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For the difference equation below: $y(k)=1/2{x(k)+x(k-1)}$ How i can find he z-domain transfer function? Thanks. |
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I assume this is homework, but transforming a difference equation to the $z$-domain is simple; just recall the time-shifting property of the transform. $$ x[n] \Leftrightarrow X(z) \rightarrow x[n-k] \Leftrightarrow z^{-k}X(z) $$ So then we have: $$ y[n] = \frac{1}{2}x[n] + x[n-1] $$ $$ Y(z) = \frac{1}{2}X(z) + z^{-1}X(z) $$ The transfer function can be written as: $$ H(z) = \frac{Y(z)}{X(z)} = \frac{1}{2} + z^{-1} $$ |
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